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Algebra, Geometry, International Mathematical Olympiads, Recreational Mathematics, Math contests, Puzzles, Brainteasers, Number Theory, Combinatorics, Logic, Paradox
Αλλαγή μεταβλητής u=6-x, οπότε
ΑπάντησηΔιαγραφήI1=(4 √(ln(9-x))/(√(ln(9-x))+√(ln(x+3)))dx =
)2
= (4 √(ln(u+3))/(√(ln(u+3))+√(ln(9-u)))du=I2
)2
I1+I2=2I1=2, άρα I1=1.