Let $A, B, C$ be three collinear points. $D, E$ are two points on one side with respect to line that contains $A, B, C$ and such that $AD∥BE$ and $BD∥CE$. $M$ is midpoint of $AC$. Then
$(DEM)=\dfrac{(ABD)+(BCE)}{2}$.
Algebra, Geometry, International Mathematical Olympiads, Math contests, Puzzles, Brainteasers, Number Theory, Combinatorics, Logic, Paradox
Δεν υπάρχουν σχόλια:
Δημοσίευση σχολίου