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$x(\sqrt[3]{2}-1)=\left ( \sqrt[3]{4}+\sqrt[3]{2}+1 \right )(\sqrt[3]{2}-1)=1$=>$\dfrac{1}{x}=\sqrt[3]{2}-1$$A=2021+(1+\frac{1}{x})^{3}=2023$
$x(\sqrt[3]{2}-1)=\left ( \sqrt[3]{4}+\sqrt[3]{2}+1 \right )(\sqrt[3]{2}-1)=1$=>$\dfrac{1}{x}=\sqrt[3]{2}-1$
ΑπάντησηΔιαγραφή$A=2021+(1+\frac{1}{x})^{3}=2023$