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f(x)=[f(x)]'e^(xlnx)= e^(xlnx) (xlnx)'(xlnx)'=1lnx + x 1/x =1lnx +1 =1lnx = 0x=e^0 = 1
f(x)=[f(x)]'
ΑπάντησηΔιαγραφήe^(xlnx)= e^(xlnx) (xlnx)'
(xlnx)'=1
lnx + x 1/x =1
lnx +1 =1
lnx = 0
x=e^0 = 1