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$tan51,5=\dfrac{h}{x}=1,257<=>x=0,8h$$hx=194=>0,8h^{2}=194=>h=15,57m$
$tan51,5=\dfrac{h}{x}=1,257<=>x=0,8h$
ΑπάντησηΔιαγραφή$hx=194=>0,8h^{2}=194=>h=15,57m$