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$\int_{-1}^{1}f(x)dx=\int_{-1}^{0}f(x)dx+\int_{0}^{1}f(x)dx<=>\int_{-1}^{0}f(x)dx=-2$άρα $\int_{0}^{-1}3f(x)dx=6$.
$\int_{-1}^{1}f(x)dx=\int_{-1}^{0}f(x)dx+\int_{0}^{1}f(x)dx<=>\int_{-1}^{0}f(x)dx=-2$
ΑπάντησηΔιαγραφήάρα $\int_{0}^{-1}3f(x)dx=6$.