$ \dfrac{1}{x-y} + \dfrac{2}{y-x} + \dfrac{3}{x-y}+ \dfrac{4}{y-x}+ \dfrac{5}{x-y} + $
$+\dfrac{6}{y-x} + \dfrac{7}{x-y}+ \dfrac{8}{y-x}+ \dfrac{9}{x-y} + \dfrac{10}{y-x} = \dfrac{Α}{x-y}$.
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Α=-5
ΑπάντησηΔιαγραφή