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Τρίτη 1 Μαΐου 2018

A Median Surprise

Let D,E,F be the midpoints of the sides of ΔABC, as shown below. Rotate triangles CDG,AEG,BFG 180 around points D,E,F, respectively, into triangles BDGb,CEGc,AFGa.
This procedure creates three congruent triangles: AGGa,BGGb, and CGGc.