$P(x) = ax^4 + bx^3 + cx^2 + dx$
ισχύουν
$P(−5) = P(−2) = P(2) = P(5) = 1$
να βρεθεί η τιμή $P(10)$.
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P(-2)=P(2)<=>4b+d=0, P(-5)=P(5)<=>25b+d=0, άρα b=d=0, P(2)=1<=>16a+4c=1, P(5)=1<=>625a+25c=1, a=-0,01, c=0,29, P(10)=-71
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