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a^3-3ab^2=11=>a^6+9a^2b^4-6a^4b^2=121 (1)ομοίως b^6+9a^4b^2-6a^2b^4=4 (2)(1)+(2)=a^6+b^6+3a^2b^4+3a^4b^2=125(a^2+b^2)^3=5^3 => a^2+b^2=5
a^3-3ab^2=11=>a^6+9a^2b^4-6a^4b^2=121 (1)
ΑπάντησηΔιαγραφήομοίως b^6+9a^4b^2-6a^2b^4=4 (2)
(1)+(2)=a^6+b^6+3a^2b^4+3a^4b^2=125
(a^2+b^2)^3=5^3 => a^2+b^2=5